Operating Systems > Linux and UNIX
linux??
lazygamer:
56k's can't go at true 56k for some reason, something like 48k perhaps. 48k does not mean 48kb or 48000 bytes(or is that bits?) per second, it actually means 4800 bytes(or is that bits?) per second.
voidmain:
56 kilobits (Kb) / 8 = 7 kilobytes (KB) of data per second. That is assuming both ends are connected at maximum capability.
In addition to that if you have a modem capable of compression you can effectively get higher transfer rates. Assuming you are transferring a text file that is capable of being compressed to half it's size (most text files compress much smaller than this) you will in effect get 14KB/s when you transfer that text file. Now compression will do you no good when transferring files that are already compressed (*.zip, *.gz, etc) because compressed files can not be compressed any more than they are.
Obviously there are other factors that will not allow the maximum connect speeds (shitty equipment, phone lines, running Windows, dropped packets, latency, etc) so you likely will only get 5 or 6KB/s max on a good connection when transferring *.zip, *.gz, or other compressed files.
[ October 01, 2002: Message edited by: void main ]
TheQuirk:
That, and in the US (and other countries, I think) they limit it to 53k. 53/8 equals to 6. And you'll probably go lower then that.
Master of Reality:
so your saying the average 56 might get 5-6 KB/s (kilobytes) not 5-6Kb/s(kilobits).
Therefore redhat 8.0 (all 5 CDs) would take 7.513 24-hour days?? (rough estimate)
[ October 01, 2002: Message edited by: The Master of Reality / Bob ]
TheQuirk:
I'm saying that the US limits 56k modems to 53kilobits. 53 divided by 8 is 6, so you'd get about 6k to 5k.
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